Good morning,
I am working on a friends MX7120, and it refuses to charge. If you leave it plugged in for a few hours, it WILL gather enough juice to run for a few minutes, but the power meter keeps dropping, even while on AC, and it will eventually shut down again.
I have appropriate voltages at the AC adapter output, and at the battery contacts in the computer. They have replaced the battery and the AC adapter prior to giving it to me. None of this has made a difference. I have tried to drop an Amprobe in-line on the AC side with a 10x multiplier and I get a zero (or almost) reading on the 6 amp scale. AC adapter says 1.6 amps. At 10x with the computer on and/or charging, I should be able to read SOMETHING! Instead I have zip.
All of the proper lights are lit, both inside & out. It seems as if the problem must be in the charging circuit, as if the computer thinks the battery is already fully charged. But again, it won't run at all without the battery, and that implies that there is more to the problem, true?
Thanks for reading all of this, your input would be appreciated!
Fred
I am working on a friends MX7120, and it refuses to charge. If you leave it plugged in for a few hours, it WILL gather enough juice to run for a few minutes, but the power meter keeps dropping, even while on AC, and it will eventually shut down again.

I have appropriate voltages at the AC adapter output, and at the battery contacts in the computer. They have replaced the battery and the AC adapter prior to giving it to me. None of this has made a difference. I have tried to drop an Amprobe in-line on the AC side with a 10x multiplier and I get a zero (or almost) reading on the 6 amp scale. AC adapter says 1.6 amps. At 10x with the computer on and/or charging, I should be able to read SOMETHING! Instead I have zip.

All of the proper lights are lit, both inside & out. It seems as if the problem must be in the charging circuit, as if the computer thinks the battery is already fully charged. But again, it won't run at all without the battery, and that implies that there is more to the problem, true?
Thanks for reading all of this, your input would be appreciated!

Fred







