Yes, take a look at the pin-in and pin-out diagram from the Intel specsheet for the 533FSB Pentium-M.ftp://download.intel.com/design/mobi...s/30526201.pdf
We already know that bridging the C15 and C16 with a fine copper wire tricks the motherboard into running the processor at 533FSB. This did increase the FSB of my pentium-M 1.7 to 533, but left it unstable at the core speed of 2.26ghz. So, I bridged G3 and H3 as well.
Now, there are reasons why I chose this particular pin. By bridging G3 and H3, you force the Vid3 pin to always report to the motherboard that it (the Vid3 pin) is low (or 0). The Pentium-M works by letting the software (Windows XP, Bios, etc) tell it when to shift states to change it's multiplier. When the pentium-M receives a request to change multipliers, it sends a request to the motherboard to increase (or decrease) the voltage based on some predetermined internal settings. It uses the 5 vid pins (F2, F3, G3, G4, and H4) to communicate to the motherboard what voltage it would like. If you look around in the Intel specsheet for the voltage table (I think its page 16), and study the voltages that the PM 1.7 shifts through (using CPU-Z for example), then you will eventually figure out that you can affect minor changes in voltage requests by changing these pins.
Now, the pin bridging I chose is not the only one that will work. When my PM1.7 is at the 6x multiplier, the voltage is 0.988, so my Vid pins are 101101 (moving from vid5 to vid0). When it is at 17x multiplier, the voltage is 1.324, which is 011000. If I permanently ground vid3, then my vids change to 100101 (which is 1.116 voltage), and 010000 (which is 1.452 voltage, a 0.128 increase).
Now, its possible to actually lock the processor down to only one voltage, but that would make it run hot all the time (like a prescott). That's why I chose vid3. It still varies the voltage when the multiplier changes, so it is still somewhat efficient.