From a chemical standpoint, there is no way to correctly deduce how much longer the battery will continue to operate.
Voltage only decreases slightly, current remains the same, and the calculation for percent remaining is measured by voltage. With discrepencies in voltage values as low as they are, never trust what Windows XP, Dell or anyone tells you, just try it out for yourself.
The equation, if you want to figure out for yourself, is the Neurnst equation, Ecell = Ecell* - (R*T*lnQ)/(nF) where R is universal gas constant, T is temperature (Kelvin), F is Faraday's Constant, n is number of moles of electrons transferred in the base equation, and Q is the relative concentrations of products.
Voltage varies in Li-on batteries by so little, it's practically impossible to tell.